Optimal. Leaf size=506 \[ \frac{2 i x \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (2,-e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{2 i x \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (2,e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 i \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (3,-e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{4 i \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (3,e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{2 x}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \tan ^{-1}\left (\sinh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right )\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{x^2 \tanh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right )}{2 a f \sqrt{a+i a \sinh (e+f x)}}+\frac{i x^2 \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \tanh ^{-1}\left (e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f \sqrt{a+i a \sinh (e+f x)}} \]
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Rubi [A] time = 0.311229, antiderivative size = 506, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {3319, 4186, 3770, 4182, 2531, 2282, 6589} \[ \frac{2 i x \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (2,-e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{2 i x \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (2,e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 i \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (3,-e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{4 i \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (3,e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{2 x}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \tan ^{-1}\left (\sinh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right )\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{x^2 \tanh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right )}{2 a f \sqrt{a+i a \sinh (e+f x)}}+\frac{i x^2 \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \tanh ^{-1}\left (e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{a f \sqrt{a+i a \sinh (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 3319
Rule 4186
Rule 3770
Rule 4182
Rule 2531
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{x^2}{(a+i a \sinh (e+f x))^{3/2}} \, dx &=-\frac{\sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \int x^2 \text{csch}^3\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx}{2 a \sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{2 x}{a f^2 \sqrt{a+i a \sinh (e+f x)}}+\frac{x^2 \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{2 a f \sqrt{a+i a \sinh (e+f x)}}+\frac{\sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \int x^2 \text{csch}\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx}{4 a \sqrt{a+i a \sinh (e+f x)}}-\frac{\left (2 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \int \text{csch}\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx}{a f^2 \sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{2 x}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 \tan ^{-1}\left (\sinh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{i x^2 \tanh ^{-1}\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{a f \sqrt{a+i a \sinh (e+f x)}}+\frac{x^2 \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{2 a f \sqrt{a+i a \sinh (e+f x)}}-\frac{\sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \int x \log \left (1-e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right ) \, dx}{a f \sqrt{a+i a \sinh (e+f x)}}+\frac{\sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \int x \log \left (1+e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right ) \, dx}{a f \sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{2 x}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 \tan ^{-1}\left (\sinh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{i x^2 \tanh ^{-1}\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{a f \sqrt{a+i a \sinh (e+f x)}}+\frac{2 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (-e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{2 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}+\frac{x^2 \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{2 a f \sqrt{a+i a \sinh (e+f x)}}+\frac{\left (2 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \int \text{Li}_2\left (-e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right ) \, dx}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{\left (2 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \int \text{Li}_2\left (e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right ) \, dx}{a f^2 \sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{2 x}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 \tan ^{-1}\left (\sinh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{i x^2 \tanh ^{-1}\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{a f \sqrt{a+i a \sinh (e+f x)}}+\frac{2 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (-e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{2 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}+\frac{x^2 \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{2 a f \sqrt{a+i a \sinh (e+f x)}}+\frac{\left (4 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}-\frac{\left (4 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{2 x}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 \tan ^{-1}\left (\sinh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{i x^2 \tanh ^{-1}\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{a f \sqrt{a+i a \sinh (e+f x)}}+\frac{2 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (-e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{2 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{a f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{4 i \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_3\left (-e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{4 i \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_3\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{a f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{x^2 \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{2 a f \sqrt{a+i a \sinh (e+f x)}}\\ \end{align*}
Mathematica [A] time = 1.76413, size = 384, normalized size = 0.76 \[ \frac{\left (\cosh \left (\frac{1}{2} (e+f x)\right )+i \sinh \left (\frac{1}{2} (e+f x)\right )\right ) \left (-\left (\frac{1}{2}-\frac{i}{2}\right ) (-1)^{3/4} \left (\cosh \left (\frac{1}{2} (e+f x)\right )+i \sinh \left (\frac{1}{2} (e+f x)\right )\right )^2 \left (4 f x \text{PolyLog}\left (2,-(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )-4 f x \text{PolyLog}\left (2,(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )-8 \text{PolyLog}\left (3,-(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )+8 \text{PolyLog}\left (3,(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )+e^2 \log \left (1-(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )-e^2 \log \left ((-1)^{3/4} e^{\frac{1}{2} (e+f x)}+1\right )+2 e^2 \tanh ^{-1}\left ((-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )-f^2 x^2 \log \left (1-(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )+f^2 x^2 \log \left ((-1)^{3/4} e^{\frac{1}{2} (e+f x)}+1\right )-16 \tanh ^{-1}\left ((-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )\right )+2 f^2 x^2 \sinh \left (\frac{1}{2} (e+f x)\right )+f x (4+i f x) \left (\cosh \left (\frac{1}{2} (e+f x)\right )+i \sinh \left (\frac{1}{2} (e+f x)\right )\right )\right )}{2 f^3 (a+i a \sinh (e+f x))^{3/2}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.047, size = 0, normalized size = 0. \begin{align*} \int{{x}^{2} \left ( a+ia\sinh \left ( fx+e \right ) \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{{\left (i \, a \sinh \left (f x + e\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\sqrt{\frac{1}{2}}{\left ({\left (-i \, f x^{2} - 4 i \, x\right )} e^{\left (2 \, f x + 2 \, e\right )} +{\left (f x^{2} - 4 \, x\right )} e^{\left (f x + e\right )}\right )} \sqrt{i \, a e^{\left (2 \, f x + 2 \, e\right )} + 2 \, a e^{\left (f x + e\right )} - i \, a} e^{\left (-\frac{1}{2} \, f x - \frac{1}{2} \, e\right )} +{\left (a^{2} f^{2} e^{\left (3 \, f x + 3 \, e\right )} - 3 i \, a^{2} f^{2} e^{\left (2 \, f x + 2 \, e\right )} - 3 \, a^{2} f^{2} e^{\left (f x + e\right )} + i \, a^{2} f^{2}\right )}{\rm integral}\left (\frac{\sqrt{\frac{1}{2}}{\left (-i \, f^{2} x^{2} + 8 i\right )} \sqrt{i \, a e^{\left (2 \, f x + 2 \, e\right )} + 2 \, a e^{\left (f x + e\right )} - i \, a} e^{\left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )}}{2 \, a^{2} f^{2} e^{\left (2 \, f x + 2 \, e\right )} - 4 i \, a^{2} f^{2} e^{\left (f x + e\right )} - 2 \, a^{2} f^{2}}, x\right )}{a^{2} f^{2} e^{\left (3 \, f x + 3 \, e\right )} - 3 i \, a^{2} f^{2} e^{\left (2 \, f x + 2 \, e\right )} - 3 \, a^{2} f^{2} e^{\left (f x + e\right )} + i \, a^{2} f^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\left (a \left (i \sinh{\left (e + f x \right )} + 1\right )\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{{\left (i \, a \sinh \left (f x + e\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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